1. H20 M H2O=2+12=14 nr moli=200/14=14.28 nr molecule =nr moli* nr lui Avog.(NA)= 14.28NA 2. H2SO4 M  H2SO4=2+64+32=98 nr moli=200/98=2.04 nr molec=2.04*NA SPER CA TE-AM AJUTAT!

Prima substanta CaCO₃ Masa moara=40+12+48=100g/mol 1mol........................100g x moli......................200g x=2moli 1mol...............................6.023*10²³ molecule 2moli...............................y y=12.046*10²³ molecule A doua substanta: Cu(OH)₂ Masa molara Cu(OH)₂=64+32+2=98g/mol 1mol..........................98g z moli........................200 z=2.04moli 1mol.................................6.023*10²³ molecule 2.04moli.............................w w=12.28692*10²³ molecule